>
>So you have the following choice:
> - encode the *whole* spec (and nothing but the spec - i.e. no tricky
>non-compliant extensions) and give yourself the label "conforming XML
tool".
> - encode the bits you feel are cost effective and label it "processes most
>XML documents, but gives 'Sorry' messages for some".
More questions/issues then:
A well-formed XML document is not required to have a DTD, internal or
external, correct? Is a well-formed parser not an XML parser that does not
have access to or does not process a DTD, internal or external? I guess I
haven't found a clear definition of what a well-formed parser is yet.
If this is true, then a well-formed parser doesn't even have to acknowledge
that entities exist except for the built in ones, and absolutely all
whitespace is preserved, right?
Thanks,
Jeremie Miller
jer@jeremie.com
http://www.jeremie.com/